Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
256 views
in Physics by (76.0k points)
closed by
A force `F` acts tangentially at the highest point of a disc of mass `m` kept on a rough horizontal plane. If the disc rolls without slipping, the acceleration of centre of the disc is:
image
A. `(2F)/(3m)`
B. `(10F)/(7m)`
C. zero
D. `(4F)/(3m)`

1 Answer

0 votes
by (87.4k points)
selected by
 
Best answer
Correct Answer - D
`F+f=Ma` ………..i
`FR=fR=(MR^(2))/2 a/R`……ii
`F-f=(Ma)/w`………..iii
`2F=(2Ma)/wimpliesa=(4F)/(3M)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...