Correct Answer - A::B::D
The point of contact between the sphere and the surface slips to the left. So the frictional force f acts towards the right.
If `a` is the linear acceleration of the centre of mass, then considering translational motion, we get
`7+f=1xxa` or `7+f=a`........i
Considering rotational motion about centre `C` we get
Net torque `=7R-fR=Ialpha`
`R[7-f]=[2/3xx1xxR^(2)]a/R`
`7-f=2/5a`..........ii
Adding eqn i and ii we get
`14=(7a)/5` or `a=10 m//s^(2)`
from eqn i `7+f=10` or `f=3N`