Correct Answer - B
First `50` m fall is under the effect of gravity only. The velocity acquired
` u= sqrt 2 gh ) = sqrt ( 2 xx 9.8 xx 500 = 10 sqrt (9.8) ms^(-1)`
Taking onward motion of prachutist with retardation ` 2 m//s^2` , v = 3 have , u = 10 sqrt 9.8 m//s ,
` a =- 2 ms^(-1) , we have , ` u = 10 sqrt 9.8 m//s ,
` a=- 2 ms^(-1) , v= 3 m//s , S= ?`
S= (v^2 -u^2)/(2 a) = (3^2 - (100 xx 9.8)) /( 2 xx (-2) = 243 m`.
Total height ` = 50 + 243 = 293 m`.