Question

An increase in intensity level of 1 dB implies an increase in intensity of (given anti `log_(10)0.1=1.2589`)
A. `1%`
B. `3.01%`
C. `26%`
D. `0.1%`

Answer 1

Correct Answer - C
Intensity level is decibel is given by
`L=10log_(10)((I)/(I_0))`
`L+1=10log_(10)((I_1)/(I_0))`
Subtracting, `1=10log_(10)((I_1)/(I_0))-10log_(10)((I)/(I_0))`
or `(1)/(10)=log_(10)((I_1)/(I))`
or `0.1=log_(10)((I_1)/(I))`
or `(I_1)/(I)=1.26`