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A pendulum clock gives correct time at `20^(@)C` at a place where `g= 10m//s^(2)`. The pendulum consists of a light steel rod connected to a heavy ball. If it is taken to a different place where `g = 10.01m//s^(2)` at what temperature the pendulum gives correct time ( `alpha` of steel of `10^(-5//@)C`)
A. `30^(@)C`
B. `60^(@)C`
C. `100^(@)C`
D. `120^(@)C`

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