If displacement `x` and velocity `v` related as `4v^(2) = 25 - x^(2)m` in a `SHM` Then time period of given `SHM` is (consider SI unit) - Sarthaks eConnect

Correct Answer - C
Given `4v^(2)= 25 - x^(2)`
Diffrentiating with respect to `t` an both sides
`8 va= -2xv rArr a = -(x)/(4)`
motion is simple harmonic
So, `omega^(2) = (1)/(4)` and `T = 2pi sqrt(4) = 4 pi`

If displacement `x` and velocity `v` related as `4v^(2) = 25 - x^(2)m` in a `SHM` Then time period of given `SHM` is (consider SI unit)

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