Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
141 views
in Physics by (79.4k points)
closed by
A ring shaped tube contain two ideal gases with equal masses and relative molar masses `M_1=32 and M_2=28.`
The gases are separated by one fixed partiotin and another movable stopper S which can move freely without friction inside the ring. The angle `alpha` as shown in the figure is ...... degrees.
image

1 Answer

0 votes
by (86.6k points)
selected by
 
Best answer
Pressure on both sides will be equal
`p_(1)=p_(2)`
i.e., `(n_(1)RT)/(V_(1))=(n_(2)RT)/(V_(2))(n=(m)/(M))`
`(m)/(M_(1)V_(1))=(m)/(M_(1)V_(2))` or `(V_(2))/(V_(1))=(M_(1))/(M_(2))=(32)/(28)=(8)/(7)`
but `(V_(2))/(V_(1))=(alpha)/(360-alpha)`
Solve to get `alpha=((360^(@))/(8+7))xx 8=192^(@)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...