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A mixture of 2 moles of helium gas (`(atomic mass)=4a.m.u`) and 1 mole of argon gas (`(atomic mass)=40a.m.u`) is kept at 300K in a container. The ratio of the rms speeds `((v_(rms)(helium))/((v_(rms)(argon))` is
A. `0.32`
B. `0.45`
C. `2.24`
D. `3.16`

1 Answer

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Correct Answer - D
`(v_("rms"_(He)))/(v_("rms"_(Ar)))=sqrt((2RT)/(m_(He)))/(sqrt((3RT)/(m_(Ar))))=sqrt((m_(Ar))/(m_(He)))=sqrt((40)/(4))=sqrt(10)~~3.16`

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