Question

A mixture of 2 moles of helium gas (`(atomic mass)=4a.m.u`) and 1 mole of argon gas (`(atomic mass)=40a.m.u`) is kept at 300K in a container. The ratio of the rms speeds `((v_(rms)(helium))/((v_(rms)(argon))` is
A. `0.32`
B. `0.45`
C. `2.24`
D. `3.16`

Answer 1

Correct Answer - D
`((v_(rms))_(He))/((v_(rms))_(Ar)) = sqrt(((M_(0))_(Ar))/((M_(0))_(He)))=sqrt(40/4)=sqrt(10)=3.16`