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A mixture of 2 moles of helium gas `(atomic mass=4amu)` and 1 mole of argon gas `(atomic mass=40amu)` is kept at 300K in a container. The ratio of the rms speeds `((v_(rms)(helium))/((v_(rms)(argon))` is
A. `0.32`
B. `0.45`
C. `2.24`
D. `3.16`

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Correct Answer - D
(d) `v_(rms(helium))/(v_(argon))=sqrt(M_(argon)/M_(helium))=sqrt(40/4)=sqrt10~~3.16

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