Question

A partical of `mass m = 1 kg` oscillates simple harmonically with angular frequency `1 rad//s`. Find the phase of the partical at `t = 1 s and 2 s`. Start calculating time when the partical moves up passing through the mean position.

Answer 1

We need to find `phi = omega t + phi_(0)` where `omega` is the angular frequency of SHM.
Since, the partical moves up at the equilibrium possition at `t = 0`, we have `phi_(0) = 0, Then , phi = t rad`
Substituting, `t= 1s, 2s, we have phi = t rad, 2rad`