Correct Answer - C
`x = A sin (omega t+ phi)`
`phi = pi//6`
`x = A sin (omega xx 0 + pi//6) = A//2`
Time taken in moving `A//2 = 7//8`
It is obvious that particle will meet again at `Q` while having covered a distance
`= 4 xx (A)/(2) = 2A`
Time required `= 4 xx (T)/(8) = (T)/(2)`