Question

Two particle of same time period `(T)` and amplitude undergo `SHM` along the same line with initial and phase of `pi//6`. If they start at the same point along the opposite. Directions. Find the time other which they will theel again for the first time
A. `T//8`
B. `T//4`
C. `T//2`
D. `T`

Answer 1

Correct Answer - C
`x = A sin (omega t+ phi)`
`phi = pi//6`
`x = A sin (omega xx 0 + pi//6) = A//2`

Time taken in moving `A//2 = 7//8`
It is obvious that particle will meet again at `Q` while having covered a distance
`= 4 xx (A)/(2) = 2A`
Time required `= 4 xx (T)/(8) = (T)/(2)`