Question

The equation of a transverse travelling on a rope is given by `y=10sinpi (0.01x-2.00t)` where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about
A. `63cm//s`
B. `75cm//s`
C. `100cm//s`
D. `121cm//s`

Answer 1

Correct Answer - A
The given equation is `y=10sinpi(0.01pix-2pit)`
Hence `omega=` coefficient of `t=2pi`
`implies` maximum speed of the particle `v_(max)=aomega=10xx2pi`
`=10xx2xx3.14=62.8=63(m)/(s)`