Question

An object of mass `0.2 kg` executes simple harmonic oscillation along the `x - axis`with a frequency of `(25//pi) Hz`. At the position `x = 0.04`, the object has Kinetic energy of `0.5 J` and potential energy `0.4 J. The amplitude of oscillations is……m.
A. `0.05m`
B. `0.06m`
C. `0.01m`
D. none of these

Answer 1

Correct Answer - B
`E=(1)/(2)momega^2A^2=(1)/(2)m(2pif)^2A^2`
`A=(1)/(2piF)sqrt((2E)/(m))`
Putting `E=K+U`, we get
`A=(1)/(2pi((25)/(pi)))sqrt((2xx(0.5+0.4))/(0.2))=0.06m)`