Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
133 views
in Physics by (91.2k points)
closed by
A closed organ pipe has length `L`. The air in it is vibrating in thirf overtone with maximum ampulitude a . The amplitude at distance`(L)/(7)` from closed of the pipe is
A. `A and B`
B. `a//2`
C. `(sqrt3)/(2)a`
D. `(1)/(sqrt2)a`

1 Answer

0 votes
by (91.8k points)
selected by
 
Best answer
Correct Answer - A
image
The figure shows variation of displacement of particles in a closed organ pipe for `3^(rd)` overtone.
For third overtone `l=(7lamda)/(4)` or `lamda=(4last)/(7)` or `(lamda)/(4)=(l)/(7)`
Hence the amplitude at P at a distance `(l)/(7)` from closed end is `a` because there is an antinode at that point.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...