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A closed organ pipe of length 1.2 m vibrates in its first overtone mode. The pressure variation is maximum at
A. `0.4 m` from the open end
B. `0.4 m` from the closed end
C. Both (a) and (b)
D. `0.8 m` from the open end

1 Answer

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Best answer
Correct Answer - A
In first overtone mode, `l=(3lamda)/(4)`
`:. (lamda)/(4)=(l)/(3)=(1.2)/(3)=0.4m`
Pressure variation will be maximum at displacement nodes, i.e., at 0.4 m from the open end.

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