Question

An elevator, in which a man is standing, is moving upward with a constant acceleration of `2 m//s^2`. At some instant when speed of elevator is `10 m//s`, the man drops a coin from a height of `1.5 m`. Find the time taken by the coin to reach the floor.
A. `(1)/(sqrt(3)) sec`
B. `(1)/(2) sec`
C. `(1)/(sqrt(2)) sec`
D. `1 sec`

Answer 1

Correct Answer - B
`d_(rel) = (1)/(2) a_(rel) t^2 rArr 1.5 = (1)/(2) (10 + 2) t^2`
`1.5 = (1)/(2) xx 12 xx t^2 rArr t = (1)/(2) sec`.