Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.9k views
in Physics by (79.4k points)
closed by
A balloon is moving along with constant upward acceleration of `1 m//s^2`. A stone is thrown from the balloon downwards with speed `10 m//s` with respect to the balloon. At the time of projectile balloon is at height `120 m` from the ground and is moving with speed `20 m//s`. Find the time required to fall on the ground by the stone after the projection.
image
A. 6 sec
B. 4 sec
C. 3 sec
D. 4.5 sec

1 Answer

0 votes
by (86.6k points)
selected by
 
Best answer
Correct Answer - A
`-120 = 10 t (1)/(2) - xx 10 xx t^2`
`t^2 - 2t - 24 = 0`
`t = 6 sec`.
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...