Question

When slow neutrons are incident on a target containing `._(92)U^(235)` , a possitle fission reactionis
`._(92)U^(235)+n rarr ._(56)Ba^(141)+_(36)Kr^(92)+3n+Q`
Estimate the amount of energy released using the following data :
`M[._(92)U^(235)]=235.04u,`
`M[._(56)Ba^(141)]=140.91u,`
`M[._(36)Kr^(92)]=91.926u,`
`M_(n)=1.0087u.`
Take `1u=1.661xx10^(-27)kg.`
`1MeV=1.602xx10^(-13)J`

Answer 1

Mass defect, `Deltam=235.04+1.0087`
`-140.91-91.926-3xx1.0087`
`Deltam=0.1866u=0.1866xx1.661xx10^(-27)kg`
Energy released, `E=(Deltam)c^(2)`
`=0.1866xx1.661xx10^(-27)(3xx10^(8))^(2)J`
`=(0.1866xx1.661xx9xx10^(-11))/(1.602xx10^(-13))MeV`
`E=174.1MeV`