Question

A simple pendulum of length 1m has bob of mass 100 g. It is displaced through an angle of `60^@` from the vertcal and then released. The kinetic energy of bob when it passes through the mean position is
A. `0.25J`
B. `0.5J`
C. `1.0J`
D. `1.4J`

Answer 1

Correct Answer - B

`K_1+U_1=K_2+U_2`
`0+mgL(1-cos60^@)=K_2+0`
`K_2=0.1xx10xx1(1-(1)/(2))`
`=0.5J`