Correct Answer - A
(a) Power due to tension =0
Power due to mg =(mg)(v) cos60^(@)
Here `" " v=sqrt(2gh)`
and `" " h=l(cos 30^(@)-cos 60^(@))=1((sqrt3)/(2)-(1)/(2))`
`:. " " v=sqrt(2xx10xx((sqrt3-1)/(2)))=sqrt(10(sqrt3-1))=2.7 ms^(-1)`
`:. "Power",P=(mgv)/(2)=(1xx10)/(2)xx27=13.5 W`