Question

A bullet is fired from a gun. The force on the bullet is given by `F=600-2xx10^(5)` t, where F is in newtons and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?
A. 9Ns
B. zero
C. `0.9Ns`
D. `1.8Ns`

Answer 1

Correct Answer - C
`F=600-2xx10^(5)t=0` implies `t=3xx10^(-3)sec`
impulse `I=int_(0)^(1)Fdt=int_(0)^(3xx10^(-3))(600-2xx10^(3)t)dt`
`=[600t-10^(5)t^(2)]_(0)^(3xx10^(-3))=0.9Nxxsec`