Question

A bullet is fired from a gun. The force on the bullet is given by `F=600-2xx10^(5)` t, where F is in newtons and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?
A. 9N-s
B. zero
C. 0.9N-s
D. 1.8N-s

Answer 1

F`=600-2xx10^(5)t=0`
t`=(600)/(2xx10^(5))=3xx10^(-3)s`
Impulse `=int_(0)^(1)` Fdt