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In previous question, if we pull the block by the force `F` making an angle theta and the block remains stationary, the value of friction force is.
image
A. `mumg`
B. `Fcostheta`
C. `(mumg)/(sintheta+mucostheta)`
D. `(mumg)/sqrt(1+mu^(2))`

1 Answer

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Best answer
Correct Answer - B
`f_(s)gtFcostheta` (Since block is stationary)
`f=Fcostheta` .

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