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A rod of weight `w` is supported by two parallel knife edges `A` and `B` and is in equilibrium in a horizontal position. The knives are at a distance `d` from each other. The centre of mass of the rod is at a distance `x` from `A`.
A. `(W x)/(d)`
B. `(W d)/(x)`
C. `(W(d - x))/(x)`
D. `(W(d - x))/(d)`

1 Answer

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Best answer
Correct Answer - D
(d) Taking torque about end `A`
`tau_B = 0`
`rArr N_1 d = W(d - x)`
`rArr N_1 = (W(d - x))/(d)`.
image.

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