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A rod of weight `w` is supported by two parallel knife edges `A` and `B` and is in equilibrium in a horizontal position. The knives are at a distance `d` from each other. The centre of mass of the rod is at a distance `x` from `A`.
A. the normal reaction at `A` is `(wx)/(d)`
B. the normal reaction at `A` is `(w(d - x))/(d)`
C. the normal reaction ar `B` is `(wx)/(d)`
D. the normal reaction at `B` is `(w(d - x))/(d)`.

1 Answer

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Best answer
Correct Answer - B::C
image
For `N_(1)`
Taking torque about `B`
`N_(1) d- w (d - x) = 0 rArr N_(1) = (w(d -x))/(d)`
For `N_(2)`
`wx - N_(2) d = 0, N_(2) = (wx)/(d)`.

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