Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
329 views
in Physics by (91.8k points)
closed by
`0.80 `gram of petroleum was burnt in a bomb calorimater which contains `2.5 kg` of water and has water equivalent `500gram` The rise in temperature was `5^(@)C` Find the calorific value of petroleum

1 Answer

0 votes
by (91.2k points)
selected by
 
Best answer
Here mass of the petroleum burnt `m_(p) = 0.80 gram`
mass of water `m = 2.5 kg = 2500 gram`
water equivalent , `w = 500 gram`
specific heat of water ` s = 1 cal g^(-1) .^(@)C^(-1)`
Kise heat gained by water and calorimeter
`Q = mx Delta T + w Delta T = 2500 xx 1 xx 5 +500 xx 5 = 15000cal`
calonific value of petroleum `= (Q)/(m_(p)) = (15000)/(08) = 18750 cal//s`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...