Here mass of the petroleum burnt `m_(p) = 0.80 gram`
mass of water `m = 2.5 kg = 2500 gram`
water equivalent , `w = 500 gram`
specific heat of water ` s = 1 cal g^(-1) .^(@)C^(-1)`
Kise heat gained by water and calorimeter
`Q = mx Delta T + w Delta T = 2500 xx 1 xx 5 +500 xx 5 = 15000cal`
calonific value of petroleum `= (Q)/(m_(p)) = (15000)/(08) = 18750 cal//s`