Question

`0.75` gram of petroleum was burnt in a bomb calorimeter which contains 2 kg of water and has a water equivalent 500 gram. The rise in temperature was `3^(@)C` . The calorific value of petroleum is `10^(n)` cal/g. Determine the value of n.

Answer 1

Correct Answer - 4
Heat absorbed by water,
`Q_(1)=sm Delta T= 1xx2000xx3 =6xx10^(3)` cal,
Heat absorbed by calorimeter,
`Q_(2) =wxxDelta T= 500xx3 =1.5xx10^(3)` cal.
Total heat produced `=Q_(1) + Q_(2)`
`=6xx10^(3) + 1.5xx10^(3) = 7.5xx10^(3)` cal.
Calorific value of fuel `=(7.5xx10^(3))/(0.75) =10^(4)` cal/g
Thus, `10^(4) cal//g =10^(n)` cal/g (Given)
`:. n=4`