Question

`40` g of Argon is heated from `40^(@)C` to `100^(@)C (R=2 cal//mol.)` What is the heat absorbed at the constant volume by the Argon?

Answer 1

Correct Answer - `[180 cal]`
Argon is monoatomic,
`C_(v) =(3)/(2)R=(3)/(2)xx2=3 cal//mol`
No. of moles of Argon, `n=(40)/(40)=1`
Heat absorbed at constant volume is
`Q=n C_(v) dT=1xx3xx(100-40)=180 cal`