Question

A stone is dropped from a height h simultaneously another stone is thrown up from the ground with such a velocity so that it can reach a height of 4h. The time when two stones cross each other is `sqrt(((h)/(kg)))` where `k = "_____"`

Answer 1

Correct Answer - 8
`S_(1)=(1)/(2)g t^(2), S_(2)=ut-(1)/(2)g t^(2)`
`S_(1)+S_(2)=h,4h=(u^(2))/(2g)impliesu=sqrt(8gh)`
`impliesut=h`
`impliessqrt(8gh)t=h`
`impliest=sqrt((h)/(8g))`