At time `t=0`, the position vector of a particle moving in the `x-y` plane is `5hatj m`.By time `t=0`.`62 sec`,its position vector has become `(5.1hati+0.4 hatj)m`.with the data answer the following questions.
The angle `theta` made by the average velocity with the positive `x` axis
A. `tan^(-1)(2)`
B. `tan^(-1)(3)`
C. `tan^(-1)(1)`
D. `tan^(-1)(4)`