Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
68 views
in Physics by (76.7k points)
closed by
A uniform bar of length `6a` and mass `8m` lies on a smooth horizontal table. Two point masses `m` and `2m` moving in the same horizontal plane with speeds `2v` and `v` respectively, strike the bar (as shown in figure) and stick to the bar after collision. Calculate (a) velocity of the centre of mass (b) angular velocity about centre of mass and (c) total kinetic energy, just after collision.
image
A. `(v)/(5a)`
B. `(v)/(15a)`
C. `(v)/(3a)`
D. `(v)/(10a)`

1 Answer

0 votes
by (76.4k points)
selected by
 
Best answer
Correct Answer - A
`(i)` Cons. Linear momentum
image
`-2m.v+2v.m=0=MV_(cm)`
`V_(cm)=0`
`(ii)` As ball sticks to Red
Conserving angular momentum about `C`
`2v.m 2a+2ma=Iomega`
image
`=((8m.36a^(2))/(12)+2m.a^(2)+m4a^(2))`
`6mv.a=30ma^(2).omega`
`rArr omega=(v)/(5a)`
`(iii) KE=(1)/(2)Iomega^(2)=(1)/(2).30ma^(2)xx(v^(2))/(25a^(2))`
`=(3mv^(2))/(5)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...