Correct Answer - A
`(i)` Cons. Linear momentum
`-2m.v+2v.m=0=MV_(cm)`
`V_(cm)=0`
`(ii)` As ball sticks to Red
Conserving angular momentum about `C`
`2v.m 2a+2ma=Iomega`
`=((8m.36a^(2))/(12)+2m.a^(2)+m4a^(2))`
`6mv.a=30ma^(2).omega`
`rArr omega=(v)/(5a)`
`(iii) KE=(1)/(2)Iomega^(2)=(1)/(2).30ma^(2)xx(v^(2))/(25a^(2))`
`=(3mv^(2))/(5)`