Correct Answer - D
Given velocity `(upsilon)`- position (x) graph is shown in figure.
We know that acceleration `a=(upsilon d upsilon)/(dx)` …(i)
From the graph, we have
`(x)/(2)+(upsilon)/(4)=1 rArr 2x+upsilon=4` ....(ii)
`rArr (d upsilon)/(dx)=-2` ....(iii)
From Eqs. (i), (ii) and (iii)
`a=(4-2x)(-2)=-8+4x rArr a=4x-8`