Correct Answer - A
`lambda_(D)=h/p =h/(sqrt(2mE)) rArr E=(h^(2))/(2mlambda^(2)) E prop 1/m` (for electron and uranium)
for photon and electron
`lambda_("photon") =lambda_("electron")` (given)
`p_("photon")=p_("electron")`
`(E_("electron"))/(E_("photon"))=(1/2 mv^(2))/(P_("photon")xxC) =((P_("electron")V)/2)/(P_("photon")xxC)=v/(2C)`