Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.9k views
in Physics by (41.6k points)
closed by
A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities `v_1 m s^(-1) and v_2 m s^(-1)` respectively making angles of `30^@ and 60^@` with respect to the original direction of motion of A. The ratio `v_1/v_2` will be
A. `sqrt3/4`
B. `4/sqrt3`
C. `1/sqrt3`
D. `sqrt3`

1 Answer

0 votes
by (57.3k points)
selected by
 
Best answer
Correct Answer - A
image
Applying the law of conservation of linear momentum along a direction perpendicular to the direction of motion (i.e. along y-axis), we get
`0+0 = 4v_1 sin30^@- v_2 sin60^@`
`4v_1 sin30^@ = v_2 sin60^@ or v_1/v_2 =(sin 60^@)/(4sin 30^@)=sqrt3/4`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...