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`vecA = 3hati + 4hatj` तथा `vecB = 12hati - 5hatj` जहाँ `hati` तथा `hatj` क्रमशः `+X-` तथा `+Y-` अक्ष की दिशा में एकांक सदिश हैं | ज्ञात कीजिए : (i) `vecA` का परिणाम तथा (ii) `vecA *vecB` का मान |

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(i) का परिणाम `=sqrt(A_(x)^(2)+A_(y)^(2))=sqrt((3)^(2)+(4)^(2))=5`.
(ii) `vecA * vecB = (3hati + 4hatj) * (12hati - 5hatj)`
`= 36hati * hati - 15hati * hatj * hati - 20hatj * hatj`.
परन्तु `hati * hati = hatj * hatj =1` तथा `hati * hatj = hatj * hati = 0`.
`therefore vecA * vecB = 36 -0+0-20 =16.`

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