Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
182 views
in Physics by (90.9k points)
closed by
यदि एकांक सदिश `hatA` तथा `hatB` के बीच कोण `theta` है, तो सिद्ध कीजिए कि `|hatA - hatB|= 2 sin "" (theta)/(2)` .

1 Answer

0 votes
by (90.2k points)
selected by
 
Best answer
`hatA` तथा `hatB` एकांक सदिश है अतः `|hatA| = |hatB| =1`
`therefore |hatA -hatB| = sqrt(|hatA|^(2) + |hatB|^(2) -2|hatA||hatB| cos theta)`
`=sqrt((1)^(2) + (1)^(2) - 2(1)(1) cos theta)`
`=sqrt(2- 2 cos theta) = sqrt(2(1 - costheta) = sqrt(2 xx (2 sin ""(theta)/(2))`
` [therefore cos theta = 1 - 2 sin^(2) (theta)/(2)]`
`= 2 sin "" (theta)/(2)`

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...