माना `vecA` तथा `vecB` का परिणामी सदिश है | तब
` vecC = vecA + vecB = (2hati - 6hatj - 3hatk) + (4hati + 3hatj - hatk)`
`=6hati - 3hatj - 4hatk`.
` therefore C = |vecC| = sqrt(6^(2) + (-3)^(2) + (-4)^(2)) = sqrt(61)`.
`vecC` के समांतर एकांक सदिश
`hatC=(hatC)/(C)(6hati-3hatj - 4hatk)/(sqrt(61))=(6)/(sqrt(61))hati-(3)/(sqrt(61))hatj-(4)/(sqrt(61))hatk.`
