Question

The resistance of conductivity cell containing 0.001 M KCl solution at 298 K is 1500 ohm. What is the cell constant if the conductivity of 0.001 M KCl solution at 298 K is `0.146xx10^(-3) S cm^(-1)`

Answer 1

Here conductivit (K)= `0.146xx10^(-3)Scm^(-1)`
resistances (R) `=1500 Omega`
`"Cell constant" =("Conductivity")/("Conductance")`
`= "Conductivity"xx Resistance"`
`=KxxR`
`:.` Conductance `" "=0.146xx10^(-3)xx1500=(1)/("resistance")`
`=0.219 cm^(-1)`