Correct Answer - D
The equation `x^(2)-px+r=0` has roots `alpha, beta` and the equation `x^(2)-qx+r=0` has roots `(alpha)/(2),2 beta.`
`impliesr =alphabetaand alpha+beta=p,`
`and (alpha)/(2)+2beta=qimpliesbeta=(2q-p)/(3)and alpha=(2(2p-q)/(3)`
`impliesalphabeta=r=2/9(2q-p)(2p-q)`