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`cos^(-1)(cos((7pi)/6))`is equal to (A) `(7pi)/6` (B) `(5pi)/6` (C) `pi/3` (D) `pi/6`

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`cos^(-1)(cos((7pi)/6))`is equal to (A) `(7pi)/6` (B) `(5pi)/6` (C) `pi/3` (D) `pi/6`
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Our expression is,
`cos^-1(cos((7pi)/6))`
`=cos^-1(cos(pi+pi/6))`
`=cos^-1(-cos(pi/6))`
`=cos^-1(-sqrt(3)/2)`
`As cos ((5pi)/6) = -sqrt3/2`,
`=cos^-1(cos((5pi)/6))`
`=(5pi)/6`
So, `B` is the correct option.
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