`sin^-1(sin((22pi)/7)) + cos^-1(cos((5pi)/3))+tan^-1(tan((5pi)/7)) + sin^-1(cos2)`
`=sin^-1(sin(3pi+pi/7)) + cos^-1(cos(2pi-pi/3)+tan^-1(tan(pi-(2pi)/7)) + pi/2-cos^-1(cos2)`
`=-sin^-1(sin(pi/7)) + cos^-1(cos(pi/3))-tan^-1(tan((2pi)/7)) + pi/2-2`
`=-pi/7+pi/3-(2pi)/7+pi/2 - 2`
`=(17pi)/42 - 2`
So, option `a` is the correct option.