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Assuming complete ionisation, the pH of 1.0 M HCl is 1. The molarity of `H_(2)SO_(4)` with the same pH is
A. 0.2
B. 0.1
C. `2.0`
D. 0.05

1 Answer

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Best answer
Correct Answer - D
pH = 1 means `[H^(+)] = 10^(-1) M`
Hence `[H_(2)SO_(4)] = (10^(-1))/(2) = (1)/(20) =0.05 M`.

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