Correct Answer - C
Ph OF 0.1 HCl`=1`
`H_(2)SO_(4) hArr H^(+)+HSO_(4)^(-)`
`HSO_(4)^(-) hArr H^(+) +SO_(4)^(2-)`
`:. H_(2)SO_(4)` ionises to give two `H^(+)` ions.
`:. 0.5 M H_(2)SO_(4)` will give 0.1 M `H^(+)` ion
`:. `the molarity of `H_(2)SO_(40 =0.05`