Question

For the reaction,
`CaCO_(3)(s) iff CaO(s)+CO_(2)(g)` partial pressure of `CO_(2)` at 1000 K is 0.003 atm. `DeltaG^(@)=27.2` kcal. Calculate the value of `DelaG`
A. 12.6 kcal
B. 15.6 kcal
C. 13.4 kcal
D. 14.2 kcal

Answer 1

Correct Answer - B
`CaCO_(3)(s)iffCaO(s)+CO_(2)(g)`
`K_(p)=P_(CO_(2))=0.003 atm`
`DeltaG=DeltaG^(@)+2.303 RT log K_(p)`
`=27.2+2.303xx2xx1000xxlog 0.003`
`=15.6 kcal (R=2 cal mol^(-1)K^(-1))`.