Question

The conversion of `A rarr B` follows second-order kinetics. Doubling the concentration of `A` will increase the rate of formation of `B` by a factor
A. `1//4`
B. 2
C. `1//2`
D. 4

Answer 1

Correct Answer - d
`r = k (A)^(2)` , when concentration is doubled
`r = k (2A)^(2) = k 4(A)^(2)` the rate becomes 4 times .