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The conversion of `A rarr B` follows second-order kinetics. Doubling the concentration of `A` will increase the rate of formation of `B` by a factor
A. `1//4`
B. `2`
C. `1//2`
D. `4`

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Correct Answer - D
`r = k(A)^(2)`, when concentration is doubled
`r = k(2A)^(2) = k4(A)^(2)` the rate becomes `4` times.

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