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The volume of 0.1M `Ca(OH)_(2)` required to neutralize 10 mL of 0.1 N HCl
A. 10 mL
B. 20 mL
C. 5 mL
D. 15 mL

1 Answer

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Best answer
Correct Answer - C
`becauseN=MxxZ`
`=0.1xx2=0.2` for `Ca(OH)_(2)`
`becauseN_(1)V_(1)=N_(2)V_(2)`
`therefore0.2xxV_(1)=0.1xx10`
`therefore V_(1)=(0.1xx10)/(0.2)=5ml`

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